Question 152262

{{{(t^2-25)/(t^2+t-20)}}} Start with the given expression.



{{{((t-5)*(t+5))/(t^2+t-20)}}} Factor {{{t^2-25}}} to get {{{(t-5)*(t+5)}}}.



{{{((t-5)*(t+5))/((t+5)*(t-4))}}} Factor {{{t^2+t-20}}} to get {{{(t+5)*(t-4)}}}.



{{{((t-5)highlight((t+5)))/(highlight((t+5))(t-4))}}} Highlight the common terms. 



{{{((t-5)cross((t+5)))/(cross((t+5))(t-4))}}} Cancel out the common terms. 



{{{(t-5)/(t-4)}}} Simplify. 



So {{{(t^2-25)/(t^2+t-20)}}} simplifies to {{{(t-5)/(t-4)}}}.



In other words, {{{(t^2-25)/(t^2+t-20)=(t-5)/(t-4)}}} where {{{t<>-5}}} or {{{t<>4}}}