Question 152004
This is an quadratic equation.
we can solve it by either factoring it or using the quadratic formula.

BY FACTORING:
6n^2 - 19n + 15 = 0
(2n - 3)(3n - 5) = 0
So
n = 3/2 or n = 5/3

BY USING THE QUADRATIC FORMULA
here a = 6, b = -19 and c = 15
Substituting into the formula:
{{{n = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
we have
{{{n = (-(-19) +- sqrt( (-19)^2-4*6*15 ))/(2*6) }}}
{{{n = (-(-19) +- sqrt( 1 ))/(2*6) }}}
{{{n = (-(-19) +- 1)/(2*6) }}}
n = (19 + 1)/12 = 5/3 or 
n = (19 - 1)/12 = 3/2