Question 151986
Solve for x:

{{{(z+2)^(-2/3) = 3}}} Raise both sides to the power of {{{(-3/2)}}}
{{{((z+2)^(-2/3))^(-3/2) = 3^(-3/2)}}} To the left side, apply the "product rule for exponents" {{{(M^a)^b = M^(ab)}}}
{{{(z+2) = 3^(-3/2)}}}
{{{z+2 = (1)/(3^(3/2))}}} This is supposed to be: {{{1}}}over{{{3^(3/2)}}} and {{{3^(3/2) = sqrt(27)}}}
{{{z+2 = 1/sqrt(27)}}} Multiply top and bottom by{{{sqrt(27)}}}
{{{z+2 = sqrt(27)/27}}} Now subtract 2 from both sides.
{{{z = sqrt(27)/27 - 2}}}
{{{z = (sqrt(27)-54)/27}}}