Question 151690
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Let x = amount of 50% saline solution added
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"amt of saline from added solution" + "amt of saline in org solution" = "desired amt of saline"
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.50x + .15(60) = .40(60+x)
.50x + 9 = 24 + .40x
.10x + 9 = 24
.10x = 15
x = 15/.10
x = 150 milliliters