Question 22763
Let larger number be x


We have the 2 numbers in ratio 9:10, so smaller number must be 9x/10


Now change numbers:


lefthand number reduces to (9x/10) - 6
righthand number reduces to x - 25


And now the LH number is twice the size of RH number, ie:


(9x/10) - 6 = 2(x-25) So solve this...
(9x/10) - 6 = 2x-50
(9x/10) = 2x-44
9x = 20x-440
11x = 440
--> x = 40

9/10ths of this is 36


so the 2 numbers are 36 and 40.


do the check too:


36-6 is 30
40-25 is 15, half of 30.


jon.