Question 151402
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8[a – b(3- 4a)] – 6a[2-a(3-b)] = 8[a – 3b+ 4ab] – 6a[2-3a+ab]
                               = [8a – 24b+32ab] – [12a-18a^2+6a^2b]
                               = 8a – 24b+32ab – 12a+18a^2-6a^2b
                               = –24b+32ab-4a+18a^2-6a^2b
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