Question 151382
{{{(x^3-y^3)/(x-y)}}} Start with the given expression.



{{{((x-y)(x^2+xy+y^2))/(x-y)}}} Factor {{{x^3-y^3}}} to get {{{(x-y)(x^2+xy+y^2)}}}



{{{(highlight((x-y))(x^2+xy+y^2))/highlight((x-y))}}} Highlight the common terms.



{{{(cross((x-y))(x^2+xy+y^2))/cross((x-y))}}} Cancel out the common terms.



{{{x^2+xy+y^2}}} Simplify.



So {{{(x^3-y^3)/(x-y)}}} simplifies to {{{x^2+xy+y^2}}}



In other words, {{{(x^3-y^3)/(x-y)=x^2+xy+y^2}}} where {{{x<>y}}}