Question 151381
 write an equation for the line that is parallel to the give line and that passes through the given point. 

y = -7/2x + 6 ; (-4,-6)

the new line has the same slope then y=-7/2x+b
and passes through (-4,-6) then -6=-(7/2)(-4)+b
then -6=14+b then b=-20

answer: y=-(7/2)x-20

find the slope of a line perpendicular to the graph of the equation. 

y = -x/5 - 7

if m and n are slopes of perpendicular lines then m*n=-1

here m =-1/5 then n =5

answer: slope is 5