Question 151372
{{{y = (1/3)x - 2}}} Start with the given equation.



{{{3y = 3((1/cross(3))x - 2)}}} Multiply both sides by 3 to eliminate the fractions.



{{{3y = x - 6}}} Distribute and multiply.



{{{3y-x=-6}}} Subtract {{{x}}} from both sides.



{{{-x+3y=-6}}} Rearrange the terms.



{{{-1(-x+3y)=-1(-6)}}} Multiply both sides by -1. This will make the x coefficient positive.



{{{x-3y=6}}} Distribute and multiply.



So the equation is now in standard form {{{Ax+By=C}}} where {{{A=1}}}, {{{B=-3}}} and {{{C=6}}}