Question 22746
Moving everything to the left side of the equal sign you get:
log x -(1/2)log 25 + 5log2 =0   (Note: all terms are base 3)
Applying the laws of logs you get:
log [x(2^5)/sqrt 25]=0
log [32x/5] = 0 (Remember the base is 3)
Therefore:
32x/5 = 3^0
32x = 5
  x = 5/32

This is only one way to do the problem.  If you know
your log laws you probably can figure out several other
ways to get the same answer.

Cheers,
Stan H.