Question 151323
This problem does not involve FOILing, but involves distribution (you use FOIL when you have two binomials). So I would double check the problem.



Anyways, here's how you would simplify the problem.



{{{4x(x^2-2x+5)}}} Start with the given expression.



{{{4x(x^2)+4x(-2x)+4x(5)}}} Distribute.



{{{4x^3+4x(-2x)+4x(5)}}} Multiply {{{4x}}} and {{{x^2}}} to get {{{4x^3}}}



{{{4x^3-8x^2+4x(5)}}} Multiply {{{4x}}} and {{{-2x}}} to get {{{-8x^2}}}



{{{4x^3-8x^2+20x}}} Multiply {{{4x}}} and {{{5}}} to get {{{20x}}}



So {{{4x(x^2-2x+5)}}} distributes and simplifies to {{{4x^3-8x^2+20x}}}



In other words, {{{4x(x^2-2x+5)=4x^3-8x^2+20x}}}