Question 151321

The solution in interval notation is: <font size="8">(</font>*[Tex \LARGE \bf{-\infty,-6}]<font size="8">)</font> *[Tex \LARGE \cup]<font size="8">(</font>*[Tex \LARGE \bf{0,\infty}]<font size="8">)</font>



Also, the solution in set notation is: *[Tex \LARGE \left\{x\|x<-6 \textrm{..or..} x>0\right\}]





Here's the graph of the solution set


{{{drawing(500,80,-11, 5,-10, 10,
number_line( 500, -11, 5 ),


circle(-6,0,0.25),
circle(-6,0,0.20),


blue(arrow(-6,0,-11,0)),
blue(arrow(-6,0.30,-11,0.30)),
blue(arrow(-6,0.15,-11,0.15)),
blue(arrow(-6,-0.15,-11,-0.15)),
blue(arrow(-6,-0.30,-11,-0.30)),



circle(0,0,0.25),
circle(0,0,0.20),


blue(arrow(0,0,5,0)),
blue(arrow(0,0.30,5,0.30)),
blue(arrow(0,0.15,5,0.15)),
blue(arrow(0,-0.15,5,-0.15)),
blue(arrow(0,-0.30,5,-0.30))


)}}}



Note:

There is an <b>open</b> circle at {{{x=-6}}} which means that we're excluding that value from the solution set.



Also, there is an <b>open</b> circle at {{{x=0}}} which means that we're excluding that value from the solution set.