Question 151305
{{{(-5r^2t^5u^6)^(3)}}} Start with the given expression.




{{{((-5)^1r^2t^5u^6)^(3)}}} Rewrite {{{-5}}} as {{{(-5)^1}}}



{{{(-5)^(3(1))r^(3(2))t^(3(5))u^(3(6))}}} Distribute the outer exponent to the inner exponents



{{{(-5)^3r^6t^15u^18}}} Multiply the exponents.



{{{-125r^6t^15u^18}}} Cube -5 to get -125



So {{{(-5r^2t^5u^6)^(3)=-125r^6t^15u^18}}}.