Question 150174
-sin A csc A - sin^2 A - cos^2 A - tan A cot A ---------> eqn 1
Okay let's isolate section by section:
1st part: {{{-sinAcscA}}}
By reciprocal identities: 
{{{sinA=1/cscA}}}----------> {{{1=sinAcscA}}}, substitute in eqn 1 and looks:
=-1-sin^2A-cos^2A-tanAcotA
2nd part:
-sin^2A-cos^2A 
By Pyth. identities:
sin^2 A + cos^2 A=1, since it has (-) on the 2nd part, then it will be = {{{-1}}}
.
Eqn 1 becomes now,
-1-1- tanA cotA
By reciprocal identities: {{{tanA=1/cotA}}} ----> {{{1=tanAcotA}}}, substituting
= {{{-1-1-1}}}
= {{{-3}}} --------------------> FINAL ANSWER <font size=5><b>no.2</font>
Thank you,
Jojo