Question 151279
{{{4x^3-54x^2+180x-125=0}}}


Group terms
{{{(4x^3-54x^2)+(180x-125)=0}}}


Factor
{{{2x^2(2x-27)+5(36x-25)=0}}}


Set each expression equal to 0
2x^2=0
x^2=0
x=0


2x-27=0
2x=27
x=27/2


36x-25=0
36x=25
x=25/36


Answer:
x=0 or 27/2 and 25/36