Question 151249
Please assistance in solving equation for x.

{{{A=(matrix(3,3,2,2,0,-4,-3,2,0,-3,-5))}}}, {{{B=(matrix(3,1,-10,2,-9))}}},  {{{X=(matrix(3,1,x,y,z))}}}, {{{AX=B}}} 
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We make the equation {{{AX=B}}}

{{{(matrix(3,3,2,2,0,-4,-3,2,0,-3,-5))(matrix(3,1,x,y,z))=(matrix(3,1,-10,2,-9))}}} 

Do you know how to find the inverse of a matrix?
If not post again asking how.  The inverse of 
matrix A is:

{{{A^(-1)=(matrix(3,3,21/2,5,2,-10,-5,-2,6,3,1))}}}

So we left-multiply both sides of the equation by this
inverse matrix, {{{A^(-1)}}}

{{{(matrix(3,3,21/2,5,2,-10,-5,-2,6,3,1))(matrix(3,3,2,2,0,-4,-3,2,0,-3,-5))(matrix(3,1,x,y,z))=(matrix(3,3,21/2,5,2,-10,-5,-2,6,3,1))(matrix(3,1,-10,2,-9))}}}

Do you know how to multiply matrices?  If not
post again asking how.

Multiply the matrices and get this:

{{{(matrix(3,3,1,0,0,0,1,0,0,0,1))(matrix(3,1,x,y,z))=(matrix(3,1,-113,108,-63))}}}

{{{(matrix(3,1,x,y,z))=(matrix(3,1,-113,108,-63))}}}

So {{{x=-113}}}, {{{y=108}}}, {{{z=-63}}}

Edwin</pre>