Question 22736
Find th real roots of:

{{{x^2 - 7x + 9 = 0}}} Solve using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}  a = 1, b = -7, and c = 9

{{{x = (-(-7)+-sqrt((-7)^2-4(1)(9)))/2(1)}}} Simplify.
{{{x = (7+-sqrt(49-36))/2}}}
{{{x = (7+-sqrt(13))/2}}}

The roots are:
{{{x = (1/2)(7 + sqrt(13))}}}
{{{x = (1/2)(7 - sqrt(13))}}}