<PRE><B>Question 151150</B>
Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. 
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If the new volume is y^3 - 13y^2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
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Use synthetic division, divide the vol by the width
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 6 | 1 - 13 + 54 - 72
............+6 - 42 + 72
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.......1 - 7 + 12 + 0
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The quotient: y^2 - 7y + 12
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Which factors to (y-4)(y-3)
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The new length = +4, new height = +3
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You can check solution: (y-6)*(y-4)*(y-3)

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