<PRE><B>Question 151114</B>
Let x = speed of 1st train
   x+5 = speed of 2nd train

After 30 minutes the distance between the two trains is equal to the sum of their distances traveled.

x(0.5) + (x+5)(0.5) = 6

(0.5)(x+x+5) = 6  ( By Factoring )

(0.5)(2x+5) = 6

2x+5 = 6/0.5   ( Eliminating 0.5 )

2x+5 = 12

2x = 12-5   ( Transposition )

2x = 7

x = 7/2     ( Divide both sides by 2 )

x = 3.5 mph  (speed of 1st train)

x+5 = 8.5 mph   (speed of 2nd train)</PRE>