Question 151095
I assume you mean
{{{2x-(2/3)y=5/3}}}

Plug in (3/2,2)
x = 3/2, y = 2
{{{2(3/2)-(2/3)2}}}
{{{3)-(4/3)}}}
{{{9/3 - 4/3 = 5/3}}}
So the second point is on the graph

Try the first point(5/2,3)
{{{2(5/2)-(2/3)3}}}
{{{5- 2}}}
{{{3}}}
3 is not equal to 5/3