Question 150990

Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r

Let x=distance ahead of Tim that Suzy must be to not to fall behind tim in the first 10 secondsof running

Distance Tim runs in the first 10 seconds=(6m/s)*10 sec=60 meters

Distance Suzy runs in the first 10 seconds plus her head start of x meters equals 4m/s*10 sec + x=40 meters plus x
Now we know that when the above two distances are equal, Tim will have caught up and in the next instance, Suzy will have fallen behind, so our equation to solve is:

60=40+x  subtract 40 meters from each side

60-40=x
x=20 meters--------------------distance ahead that Suzy must be so as not to fall behind in the first 10 seconds

MAYBE YOU CAN DO THE GRAPH 

CK
20+4*10=60
60=60

Hope this helps---ptaylor