Question 151054
1.{{{y-2x=1}}}
2.{{{2y+3x=16}}}
Multiply eq. 1 by (-2),
1.{{{-2(y-2x)=(-2)1}}}
1.{{{-2y+4x=-2}}}
Now add it to eq. 2 to get rid of y,
{{{-2y+4x+2y+3x=-2+16}}}
{{{7x=14}}}
{{{highlight(x=2)}}}
From eq. 1,
1.{{{y-2x=1}}}
{{{y-2(2)=1}}}
{{{y-4=1}}}
{{{highlight(y=5)}}}
The answer checked graphically.
{{{drawing( 300, 300, -8, 8, -8, 8,grid( 1 ),circle( 2,5, .2 ),graph( 300, 300, -8, 8, -8, 8, 1+2x, (16-3x)/2)) }}}