Question 150954
Use a system of equations to solve the word problem. 
The perimeter of a rectangle is 56 inches
2L + 2W = 56
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and its area is 192 square inches
L*W = 192
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What are the dimensions?
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Rearrange to get:
L = 28 -W
Substitute to get:
(28-W)W = 192
28w - W^2 = 192
W^2 -28W + 192 = 0
(w-12)(w-16) = 0
W = 12 and L = 16
or
W = 16 and L = 12
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Cheers,
Stan H.