Question 146423
P(A)=.02	P(B)=.02	A=Alternator #1		B=Alternator #2

a)P(A ∩ B) = P(A)P(B) = (.02)(.02) = .0004

b)(.98)(.98) = 0.9604

c)[P(alt 1 fails) * P(alt 2 doesn't fail)] + [P(alt 1 doesn't fail) * P(alt 2 fails)] = [ .02 * .98] + [.98 * .02] = .0392