Question 150932
{{{48x^2y+20xz+12xy+5z}}} Start with the given expression


{{{(48x^2y+20xz)+(12xy+5z)}}} Group the terms into two groups



{{{4x(12xy+5z)+1(12xy+5z)}}} Factor out the GCF {{{4x}}} out of the first group. Factor out the GCF {{{1}}} out of the second group



{{{(4x+1)(12xy+5z)}}} Since we have the common term {{{12xy+5z}}}, we can combine like terms


So {{{48x^2y+20xz+12xy+5z}}} factors to {{{(4x+1)(12xy+5z)}}}