Question 150880
1. x^2+x-6
Since this has a + and a -, then you set it up like this:
(x+)(x-)
Factors of 6 whose difference is 1: 3 and 2
The higher number (3) will go in the (x+), since the x term is positive.
(x+3)(x-2)


2.3x^2+11x+10
Since this has two +'s, you set it up like this:
(3x+)(x+)
Since 3 is prime, it has to be 3x and x.  Then the other two numbers must be so that one number times 3x + the other number times x equals 11x.

Those number would be 2 and 5, but how do you put them into (3x+)(x+)?
(3x+2)(x+5) foils out to 3x^2+17x+10, so it's not that way. so it's:
(3x+5)(x+2)