Question 150860
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Which do you mean?

This:

{{{(a/b)(2x-12)=c/d}}}

or this:

{{{a/b(2x-12)=c/d}}}

????

If you meant this:

{{{(a/b)(2x-12)=c/d}}}

Clear of fractions by multiplying both sides by {{{bd}}}

{{{(bd)*(a/b)(2x-12)=(bd)*(c/d)}}}

{{{(cross(b)d)*(a/cross(b))(2x-12)=(b*cross(d))*(c/cross(d))}}}

{{{ad(2x-12)=bc}}}

{{{ad*2x-ad*12=bc}}}

{{{2adx-12ad=bc}}}

Get the term in x on one side by itself, or
as they sometimes say, isolate the term with x.
I'll isolate it on the left:

{{{2adx=bc+12ad}}}

Solve for x by dividing both sides of the equation by
what is multiplied by x, namely {{{2ad}}}

{{{(2adx)/(2ad)=(bc+12ad)/(2ad)}}}

{{{(cross(2ad)x)/(cross(2ad))=(bc+12ad)/(2ad)}}}

{{{x=(bc+12ad)/(2ad)}}}

Warning! Leave the answer like that!  Don't think you can
do any canceling on the right for you cannot! The {{{12ad}}}
is ADDED not MULTIPLIED.

---------------------------------------------------

If you meant this:

{{{a/b(2x-12)=c/d}}}

Clear of fractions by multiplying both sides by {{{b(2x-12)}}}
a shortcut for which is known as cross-multiplying:

{{{ad=bc(2x-12)}}}

{{{ad=2bcx-12bc}}}

Get the term in x on one side by itself, or
as they sometimes say, isolate the term with x.
I'll isolate it on the right this time:

{{{ad+12bc=2bcx}}}

Solve for x by dividing both sides of the equation by
what is multiplied by x, namely {{{2bc}}}

{{{(ad+12bc)/(2bc)=(2bcx)/(2bc)}}}

{{{(ad+12bc)/(2bc)=(cross(2bc)x)/cross(2bc)}}}

{{{(ad+12bc)/(2bc)=x}}}

or if you don't like x on the right, then write it
on the left :-)

{{{x=(ad+12bc)/(2bc)}}}

Warning! As before, leave the answer like that!  Don't think 
you can do any canceling for you cannot! The {{{12bc}}}
in the numerator is ADDED, not MULTIPLIED.

Edwin</pre>