Question 150830
the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle


2w+2L=66
2(2w)+2(L+22)=136


Solve for 2w in the first equation
2w=66-2L


Plug that into the second equation
2(66-2L)+2(L+22)=136


Distribute
132-4L+2L+44=136


Combine like terms
176-2L=136


Subtract 176 from both sides
-2L=-40


Divide both sides by -2
L=20


2w=66-2L
2w=66-2(20)
2w=66-40
2w=26
w=13


Answer:
Length=20m
Width=13m