Question 150737
{{{(40*a^3*b^6)^(1/3)=(40)^(1/3)*(a^3)^(1/3)*(b^6)^(1/3)}}}
{{{(40*a^3*b^6)^(1/3)=(5*8)^(1/3)*(a^1)*(b^2)}}}
{{{(40*a^3*b^6)^(1/3)=(5)^(1/3)*(8)^(1/3)*(a)*(b^2)}}}
{{{(40*a^3*b^6)^(1/3)=2(5)^(1/3)ab^2)}}}