Question 150680
1)
{{{L=(D/(1-((1/2)^(n/H))))}}} I assume that this is the formula.
{{{L=(2.5/(1-((1/2)^(24/14))))}}}
{{{L=(2.5/(1-.304753))}}}
{{{L=2.5/.695247}}}
L=3.59585 mg
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2)
{{{L=(D/(1-((1/2)^(n/H))))}}} 
{{{5.58=(2.5/(1-((1/2)^(n/14))))}}} 
Let x=1-((1/2)^(n/14))
5.58=2.5/x 
x=2.5/5.58
x=.448029
Let y=(1/2)^(n/14)
1-y=.448029
-y=.448029-1
y=1-.448029
y=.551971
Let z=n/14
.5^z=.551971
log[.5](.5^z)=log[.5](.551971)
z=log[.5](.551971)
log[.5](.551971)=log[10](.551971)/log[10](.5)=.857336
n/14=.857336
n=14*.857336
=12.0027 hrs
So 2.5 mg must be given every 12 hrs.
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3)
{{{L=(5/(1-((1/2)^(12/14))))}}}
L=11.1618 mg
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Ed