Question 150647
{{{6y^2-54}}} Start with the given expression



{{{6(y^2-9)}}} Factor out the GCF {{{6}}}



{{{6(y^2-3^2)}}} Rewrite {{{9}}} as {{{3^2}}}



{{{6(y+3)(y-3)}}} Factor {{{y^2-3^2}}} to get {{{(y+3)(y-3)}}} through the use of difference of squares



So {{{6y^2-54}}} factors to {{{6(y+3)(y-3)}}}