<PRE><B>Question 150544</B>
How do I solve this equation?
4 to the power of x times two to the power of x squared, equal to 27 to the power of x.
:
{{{4^x*2^x^2 = 27^x}}}
:
Using the log equiv of exponents
{{{x*log(4) + x^2*log(2) = x*log(27)}}}
:
.602x + .301x^2 = 1.431x
:
divide equation by x
.602 + .301x = 1.431
.301x = 1.431 - .602
x = {{{.829/.301}}}
x ~ 2.755</PRE>