Question 150468
Go back to the general formula for a parabola which is
{{{y = ax^2 + bx + c}}}
The formula for the x-coordinate of the vertex is {{{(-b) / (2a)}}}
With the parabola {{{y = -2x^2}}},
{{{a = -2}}}
{{{b = 0}}}
{{{c = 0}}}
So, {{{x = 0 / 2*(-2) = 0}}}
and
{{{y = -2*(0)^2}}}
{{{y = 0}}}
So, the vertex of this parabola is (0,0). You are asked to keep the
shape the same, but move the vertex to (-3,2)
I can say {{{(-b) / (2a) = -3}}}
I don't want {{{a}}} to change, because that would change the shape, so
{{{a = -2}}}
{{{(-b) / 2*(-2) = -3}}}
{{{-b = 12}}}
{{{b = -12}}}
So far,  I have {{{y = -2x^2 - 12x + c}}}
I can use (-3,2) to find {{{c}}} 
{{{2 = -2*(-3)^2 - 12*(-3) + c}}}
{{{2 = -18 + 36 + c}}}
{{{c = 2 + 18 - 36}}}
{{{c = -16}}}
{{{y = -2x^2 - 12x - 16}}} answer
I'll plot both these equations
{{{ graph( 600, 600, -10, 10, -10, 10, -2x^2, -2x^2 - 12x - 16) }}}
 Each vertex looks OK