Question 150367
{{{y(x)=x^2+2x-15}}}
Replace x with the value and solve for y.
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{{{y(-4)=(-4)^2+2(-4)-15}}}
{{{y(-4)=16-8-15}}}
{{{y(-4)=-7}}}
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{{{y(-3)=(-3)^2+2(-3)-15}}}
{{{y(-3)=9-6-15}}}
{{{y(-3)=-12}}}
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{{{y(-2)=(-2)^2+2(-2)-15}}}
{{{y(-2)=4-4-15}}}
{{{y(-2)=-15}}}
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{{{y(-1)=(-1)^2+2(-1)-15}}}
{{{y(-1)=1-2-15}}}
{{{y(-1)=-16}}}
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{{{y(0)=(0)^2+2(0)-15}}}
{{{y(0)=0+0-15}}}
{{{y(0)=-15}}}
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{{{y(1)=(1)^2+2(1)-15}}}
{{{y(1)=1+2-15}}}
{{{y(1)=-12}}}
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{{{y(2)=(2)^2+2(2)-15}}}
{{{y(2)=4+4-15}}}
{{{y(2)=-7}}}

{{{drawing( 300, 300, -6, 5, -20, 5,grid( 1 ),
circle( -4, -7, .2 ),
circle( -3, -12, .2 ),
circle( -2, -15, .2 ),
circle( -1, -16, .2 ),
circle( 0, -15, .2 ),
circle( 1, -12, .2 ),
circle( 2, -7, .2 ),
graph( 300, 300, -6, 5, -20, 5, x^2+2x-15))}}}