Question 150312
{{{abs(3-2i)=sqrt(3^2+2^2)=sqrt(13)}}}
{{{3-2i=sqrt(13)(3/sqrt(13)-2i/sqrt(13))}}}
{{{cos(A)=3/sqrt(13)}}}
{{{A=33.7}}} or {{{A=360-33.7=326.3}}}
Since, 3-2i is in the 4th quadrant, then A=326.3
{{{3-2i=sqrt(13)(cos(326.3)+i*sin(326.3))}}}
Looks like #4.