Question 150350
You can solve this in 2 ways, we'll go to the faster one first:
{{{A=6}}}*{{{(V)^(2/3)}}}
Divide the whole eqn by 6 then multiply exponent ^3/2 the whole eqn so we can cancell the exponent of the unknown, {{{V}}}
{{{cross(12)2/cross(6)1}}}={{{cross(6)/cross(6)}}}*{{{V^(2/3)}}}
{{{2^(3/2)}}}=V^(2/3)(3/2)={{{V^(6/6)=V}}}, oks
Continuing,
{{{V=2.8284271}}} -----------> for the Volume
.
For other eqn, we can go for the formula for Area since it is given, then go for the formula in finding the volume:
{{{A=6s^2}}}, s=sides of the cube
{{{12/6 = s^2}}}, {{{s=sqrt(2)}}},{{{s=1.4142136}}}
For the Volume,
{{{V=s^3=1.4142136^3}}}
{{{V=2.8234271}}} -----------> for the Volume
Thank you,
Jojo