Question 150431
By distributive right,
{{{4x(x-2)-5x(x-1)=2}}} -------> working equation
{{{4x^2-8x-5x^2+5x=2}}}
{{{-x^2-3x=2}}} ---------------> {{{x^2+3x+2=0}}}
{{{(x+2)(x+1)=0}}}
{{{x=-2}}}, {{{x= -1}}}
Check it out, substitute {{{x=-2}}} or {{{x=-1}}}in working equation you get equal value, "2=2"
Thank you,
Jojo