Question 150428
If you have:
{{{ (p^2-1) / (p+1)^2 }}}
.
Notice that the numerator (p^2-1) can be factored:
(p^2-1) = (p-1)(p+1)
.
And, the denominator (p+1)^2 can be rewritten as:
(p+1)^2 = (p+1)(p+1)
.
So, instead of:
{{{ (p^2-1) / (p+1)^2 }}}
We can rewrite as:
{{{ ((p-1)(p+1)) / ((p+1)(p+1)) }}}
.
After canceling terms we get:
{{{ (p-1) / (p+1) }}}