Question 150429
Your problem gives you:
V=48T^2
where
V is the "vertical leap"
T is the "hang time"
.
Now, they want to know the "hang time" if the "vertical leap" is 25 inches.  So, plug in the given value (V) and solve for T:
V=48T^2
25=48T^2
25/48 = T^2
0.521 = T^2
sqrt(0.521) = T
0.722 seconds = T