Question 150146
x=2 is a vertical line.
A line perpendicular to a vertical line must be horizontal.
Horizontal lines have a constant y. 
So, we know the y coordinate of point B must be 1.
{{{drawing( 300, 300, -10, 10, -5, 5,grid( 1 ),locate(-5,1.5,A),circle( -4, 1, .2 ),green(line( 2, -12, 2, 12)))}}}
To be a bisector, the vertical x=2 line must be the same x distance from Point A and Point B.
The x-distance from line x=2 to (-4,1) equals 
{{{2-(-4)=6}}}
6 units to the right from x=2 is x=2+6=8.
Point B must be at (8,1).
{{{drawing( 300, 300, -10, 10, -5, 5,grid( 1 ),locate(-5,1.5,A),circle(8,1,.2),locate(9,1.2,B),blue(line(-4,1,8,1)),circle( -4, 1, .2 ),green(line( 2, -12, 2, 12)))}}}