Question 150128

.
You need to apply:
d = rt
where
d is distance
r is rate or speed
t is time
.
"time to arrive at St Paul" = "stop-over time" + "flying time"
"stop-over time" = 1 hour
"flying time" = 1150/300 = 3.83 hours
.
"time to arrive at St Paul" = 1 + 3.83 = 4.83 hours
.83 * 60 = 50 minutes
"time to arrive at St Paul" = 4 hours 50 minutes
.
9:30 am +  "4 hours 50 minutes" = 2:20 PM