Question 150080
Find the area of a triangle if side a = 3, and sides b and c = 2.
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Draw it with side a as the base.  Since sides b & c = 2, an altitude from vertex A makes to right triangles of equal area.
Each right triangle has hypotenuse = 2 and base = 1.5
Use Pythagoras to find the altitude, = sqrt (2^2 - 1.5^2)
= sqrt(4-2.25)
=sqrt(1.75)
The area is bh/2, = 3*sqrt(1.75)/2
= apx 1.9834 sq units