Question 150006
 1 + x-1
-----+ -------
x+2 + x-2
:
{{{1/((x+2))}}} + {{{((x-1))/((x-2))}}}
Common denominator: (x+2)(x-2)
{{{((x-2) + (x+2)(x-1))/((x+2)(x-2))}}} = {{{(x - 2 + (x^2+x-2))/((x+2)(x-2))}}} ={{{(x - 2 + x^2 + x - 2)/((x+2)(x-2))}}} = {{{(x^2 + 2x - 4)/((x+2)(x-2))}}}