Question 150015
let t=time in months __ a=2p (doubling) __ r=.05


a=p(1+(r/12))^t __ dividing by p __ 2=(1+(.05/12)^t __ taking log __ log(2)=t*log(1+(.05/12)


dividing by log(1+(.05/12) __ [log(2)]/[log(1+(.05/12)]=t


t=166.7 (approx) __ should be 167 to get final compounding