Question 149982
Find y as a function of x; the constant C is a positive number. 
:
ln(y-1) + ln(y+1) = -x + C 
:
ln[(y-1)*(y+1)] = - x + c; adding logs means multiply
:
ln(y^2 - 1) = -x + c; FOILed
:
{{{y^2 - 1 = e^(-x+c)}}}; find {{{e^x}}} of both sides 
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{{{y^2 = 1 + e^(-x+c)}}}; add 1 to both sides:
:
y = {{{sqrt(1 + e^(-x+c))}}}; find the square root of both sides
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