Question 149994
If you started with:
2x^3 - 6x = 0
A "common factor" for both terms is 2x -- pulling it out leaves:
(2x)(x^2 - 3) = 0
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Looking at the above, if either (2x) OR (x^2 - 3), it will drive it to zero.
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So, to find your solutions, set EACH term to zero and solve:
(2x)=0
x=0 (solution 1)
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(x^2 - 3)=0
x^2 = 3
x = sqrt(3) (solution 2)
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Therefore,
x = {0, sqrt(3)}