Question 149964
let x- Daisy's age
let y- Cecile's age
    x-5 Daisy's age 5 years ago
    y-5 Cecile's age 5 years ago 

(x-5)+(y-5)= 45
x-5+y-5= 45=5+5
x+y= 55          
y= -x+55 -- equation 1

Cecile is now four times as old as Daisy so, 
  4x=y --equation 2

4x=y: Substitute y from equation 1
4x= -x+55
4x+x=55
5x= 55
Divide both sides by 5 to eliminate the numerical coefficient
5x/5= 55/5
x= 11
Daisy is 11 years old.

y=-x+55
since x is equal to eleven, so
y= -11+55
y= 44
Cecile is 44 years old.