<PRE><B>Question 149928</B>
Suppose that 10 computer chips are drawn from a box containing 12 good chips and 4 defective chips.
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These are binomial problems with p = 12/16 = 3/4, q = 1/4, n=10 
What is the probability that
a. P(exactly 4 of the chips are defective) = 10C4(3/4)^6(1/4)^4  
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b. P(all 10 of the chips are good) = 10C10(3/4)^10(1/4)^0 
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c. P(exactly 8 of the chips are good) = 10C8(3/4)^8(1/4)^8 
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Comment: None of my answers agree with your posted answers.
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Cheers,
Stan H.

the answers are:
a. 924/8008
b. 66/8008
c. 2970/8008\
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