Question 149833
Well you can't solve it (since it's not an equation), but you can factor


{{{4x^2+20x+5y+xy}}} Start with the given expression.



{{{4x^2+20x+xy+5y}}} Rearrange the terms



{{{(4x^2+20x)+(xy+5y)}}} Group like terms



{{{4x(x+5)+y(x+5)}}} Factor out the GCF {{{4x}}} out of the first group. Factor out the GCF {{{y}}} out of the second group



{{{(4x+y)(x+5)}}} Since we have the common term {{{x+5}}}, we can combine like terms


So {{{4x^2+20x+5y+xy}}} factors to {{{(4x+y)(x+5)}}}