Question 149824
The goal is to manipulate the equation into the "slope-intercept" form:
y = mx + b
where
m is the slope
b is the y-intercept at (0, b)
.
Your problem:
3x+4y=8 
first subtract 3x from both sides:
4y= -3x + 8 
Now, divide both sides by 4:
y = (-3/4)x + 2
.
You now have:
slope is -3/4
and
y-intercept is (0,2)